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What is the solution to -x plus 3y equals 1 and 4x plus 5y equals 13?
-x+3y=14x+5y=13first I'll solve for y-x+3y=13y=x+1y=x/3+1/3-->plug this in for y into the other equation4x+5(x/3+1/3)=134x+5x/3+5/3=1317x/3=34/317x=34x=2--->plug this in for x in either equation and solve for y-x+3y=1-2+3y=13y=3y=1, x=2
Is 05 a solution to 5x-3y15?
If you are asking if x=0, y=5 is a solution to 5x-3y=15, then no. 0, -5 would be as if you sub in 0 for x you get 5(0) -3y=15, i.e. -3y=15, i.e. y=-5
What is the y-intercept for line 3y plus 2x equals -x plus 5?
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
How do you slove this by elimation -x plus 3y equals 5 -x-3y equals 1?
-x+3y=5-x-3y=1break apart the equation by setting the two variable expressions equal to 1-x+3y=1 and 5-x-3y=1now in the seperate equations, combine all like terms-x+3y=1 and -x-3y=-4now the choice is yours you can choose to solve for x by eliminating y or vice versa. i'll solve for yyou want to first line up the equations vertically with corresponding like terms-x+3y=1-x-3y=-4 to eliminate x subtract one equation from the other(bottom-top)= new bottom equation-x+3y=1-6y=-5y= 5/6-x+3(5/6)=1 subsitiute 5/6 for yx= 3/2 and y= 5/6
What is the solution of x plus y equals -2 and 2x plus 3y equals -9?
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
