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-x+3y=14x+5y=13first I'll solve for y-x+3y=13y=x+1y=x/3+1/3-->plug this in for y into the other equation4x+5(x/3+1/3)=134x+5x/3+5/3=1317x/3=34/317x=34x=2--->plug this in for x in either equation and solve for y-x+3y=1-2+3y=13y=3y=1, x=2
If you are asking if x=0, y=5 is a solution to 5x-3y=15, then no. 0, -5 would be as if you sub in 0 for x you get 5(0) -3y=15, i.e. -3y=15, i.e. y=-5
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
-x+3y=5-x-3y=1break apart the equation by setting the two variable expressions equal to 1-x+3y=1 and 5-x-3y=1now in the seperate equations, combine all like terms-x+3y=1 and -x-3y=-4now the choice is yours you can choose to solve for x by eliminating y or vice versa. i'll solve for yyou want to first line up the equations vertically with corresponding like terms-x+3y=1-x-3y=-4 to eliminate x subtract one equation from the other(bottom-top)= new bottom equation-x+3y=1-6y=-5y= 5/6-x+3(5/6)=1 subsitiute 5/6 for yx= 3/2 and y= 5/6
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.
-x+3y=14x+5y=13first I'll solve for y-x+3y=13y=x+1y=x/3+1/3-->plug this in for y into the other equation4x+5(x/3+1/3)=134x+5x/3+5/3=1317x/3=34/317x=34x=2--->plug this in for x in either equation and solve for y-x+3y=1-2+3y=13y=3y=1, x=2
If you are asking if x=0, y=5 is a solution to 5x-3y=15, then no. 0, -5 would be as if you sub in 0 for x you get 5(0) -3y=15, i.e. -3y=15, i.e. y=-5
start with 2x - 3y = 5 add 3y to each side, 2x - 3y + 3y = 5 + 3y :: 2x = 5 + 3y subtract 5 from each side, 2x - 5 = 5 - 5 + 3y :: 2x - 5 = 3y divide each side by 3, (2x - 5)/3 = (3y)/3 :: (2/3)x - (5/3) = y the slope is the coefficient of "x" when the equation takes the form y = mx +b Therefore, the slope of the line is 2/3, approximately 0.667
Solve for y.2x - 3y = 52x - 2x - 3y = -2x + 5-3y = -2x + 5-3y/-3 = -2x/-3 + 5/-3y = (2/3)x - 3/5Clearly you see that the slope is 2/3.
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
Add the two equations together. The x disappears. 2y - x = 3 + x = 3y - 5 ------------------------ 2y = 3y -2 Can you finish it from there?
3y = 5xy = x + 23y = 5x3(x + 2) = 5x3x + 6 = 5x3x - 3x + 6 = 5x - 3x6 = 2x6/2 = 2x/23 = xy = x + 2 = 3 + 2 = 5Thus, the solution of the set is (3, 5)Check:
3y-x=4 is the same as 3y=x+4 so y=1/3 x+4/3 and the slope is 1/3 The other equation is 3y=x+5 so y=1/3x+5/3. The slope is 1/3 again Since they have the same slope but different y intercepts they are parallel.
You are looking for the solution to the function 2x - 3y = 7.This means that when you substitute 5 for x and 1 for y, the equation makes sense logically.(2*5) - (3*1) = 10 - 3 = 7.This makes sense logically.
-x+3y=5-x-3y=1break apart the equation by setting the two variable expressions equal to 1-x+3y=1 and 5-x-3y=1now in the seperate equations, combine all like terms-x+3y=1 and -x-3y=-4now the choice is yours you can choose to solve for x by eliminating y or vice versa. i'll solve for yyou want to first line up the equations vertically with corresponding like terms-x+3y=1-x-3y=-4 to eliminate x subtract one equation from the other(bottom-top)= new bottom equation-x+3y=1-6y=-5y= 5/6-x+3(5/6)=1 subsitiute 5/6 for yx= 3/2 and y= 5/6