Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2.
Chat with our AI personalities
-x+3y=14x+5y=13first I'll solve for y-x+3y=13y=x+1y=x/3+1/3-->plug this in for y into the other equation4x+5(x/3+1/3)=134x+5x/3+5/3=1317x/3=34/317x=34x=2--->plug this in for x in either equation and solve for y-x+3y=1-2+3y=13y=3y=1, x=2
If you are asking if x=0, y=5 is a solution to 5x-3y=15, then no. 0, -5 would be as if you sub in 0 for x you get 5(0) -3y=15, i.e. -3y=15, i.e. y=-5
3y+2x = -x+5 y = -x+5/3 So the y intercept is 5/3
-x+3y=5-x-3y=1break apart the equation by setting the two variable expressions equal to 1-x+3y=1 and 5-x-3y=1now in the seperate equations, combine all like terms-x+3y=1 and -x-3y=-4now the choice is yours you can choose to solve for x by eliminating y or vice versa. i'll solve for yyou want to first line up the equations vertically with corresponding like terms-x+3y=1-x-3y=-4 to eliminate x subtract one equation from the other(bottom-top)= new bottom equation-x+3y=1-6y=-5y= 5/6-x+3(5/6)=1 subsitiute 5/6 for yx= 3/2 and y= 5/6
x + y = -2 2x + 3y = -9 You solve this by elimination - multiply both sides of first equation by 3, then subtract, solve for x, then substitute in any of the equations to solve for y 3x + 3y = -6 2x + 3y = -9 subtracting, x = 3 substituting into 1st equation, y = -2-3 = -5