start with 2x - 3y = 5 add 3y to each side, 2x - 3y + 3y = 5 + 3y :: 2x = 5 + 3y subtract 5 from each side, 2x - 5 = 5 - 5 + 3y :: 2x - 5 = 3y divide each side by 3, (2x - 5)/3 = (3y)/3 :: (2/3)x - (5/3) = y the slope is the coefficient of "x" when the equation takes the form y = mx +b Therefore, the slope of the line is 2/3, approximately 0.667
The slope is 5. Parallel lines always have the same slope.
What is the slope of the line defined by the equation shown below? 5x + 2y = 10 Group of answer choices 2/5 5/2 -2/5 -5/2
4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4
The slope is -5. The x- and y-intercepts are both zero. In other words, it passes through the origin.
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
That line is horizontal on the graph. Its slope is zero.
Undefined slope.
X=5 is a vertical line, so it has no slope. When I say it has no slope, I don't mean the slope is 0, I mean the slope is nonexistent.
That line is horizontal on the graph. Its slope is zero.
Slope: -9
The slope is -0.2
The slope is 5.
When the equation of a line is written in standard form: y = mx + c, the slope of the line is m. Here, y = 3x + 5 so slope = 3
5
7
11
The slope is 5. Parallel lines always have the same slope.