x2 + x - 1 = 0
Using the quadratic formula this gives us:
x = (-1 + or - (-12 - (4 * 1 * -1))1/2) / 2 * 1
x = (-1 + or - (1 - - 4)1/2) / 2
x = (-1 + or - 51/2) / 2
x = 0.618 and -1.618 (Both given to 3 decimal places only)
Note: x1/2 means the square root of x.
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
It has no solutions because the discriminant of the quadratic equation is less than zero.
This quadratic equation has no solutions because its discriminant is less than zero.
There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
x2+7x+3 = 0 Using the quadratic equation formula the solutions are:- x = -6.541381265 or x = -0.4586187349
There are no real solutions because the discriminant of the quadratic equation is less than zero.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
It has no solutions because the discriminant of the quadratic equation is less than zero.
Oh, dude, for this quadratic equation x^2 - 5x + 4 = 0, the solutions are just the roots of the equation. You can find them by either factoring the quadratic or using the quadratic formula. So, like, the solutions are x = 1 and x = 4. Easy peasy lemon squeezy!
This quadratic equation has no solutions because its discriminant is less than zero.
x2 + 49 = 0
There are no real solutions to this equation because you cannot take the square root of a negative number. However,x2 + 4 = 0x2 = -4sqrt(x2) = sqrt(-4)x = 2i, -2ihere are the imaginary solutions.
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
None because without an equal it is not an equation. But if it was in the form of x2+7x+12 = 0 then it would have 2 solutions which are x = -3 and x = -4
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis