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395000 meters/9000 seconds is 43.889 meters/second

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Q: What is the speed of a plane traveling 395000 meters in 9000 seconds?
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A plane traveling at 80 ms lands on a runway and comes to rest after 10 seconds what was the distance it traveled down the runway before it stopped?

The distance the plane traveled before stopping can be calculated by using the formula: distance = initial velocity * time + (1/2) * acceleration * time^2. Given initial velocity 80 m/s and time 10 seconds, and assuming acceleration is 0 m/s^2 (since the plane comes to rest), the distance traveled would be 800 meters.


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What was its speed a plane travels 395,000 meters in 9000 seconds.?

Oh, dude, let me break it down for you. So, to find the speed, you just divide the distance by the time taken, like basic math stuff. So, 395,000 meters divided by 9000 seconds gives you a speed of 43.89 meters per second. Boom, there you have it!


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