5
It depends on whether the room is 8 foot x 10 foot or 8 metres x 10 metres or 8 cubits x 10 cubits or whatever!
8' x 10' = 80 square feet
To determine how many 8-inch square tiles will fit into a 224 square foot room, first convert the room's area into square inches. Since 1 square foot equals 144 square inches, a 224 square foot room has 32,256 square inches (224 x 144). Each 8-inch tile has an area of 64 square inches (8 x 8). Dividing the total area of the room by the area of one tile, you get 505 tiles (32,256 ÷ 64).
Assuming the room is 8 ft by 10 ft (the question does not say so), the area would be 8*10 = 80 square feet
Just multiply the numbers together. 8*9.6=76.8 sq ft
8*10=80 sqf, actually...
It depends on whether the room is 8 foot x 10 foot or 8 metres x 10 metres or 8 cubits x 10 cubits or whatever!
8 ft x 10 ft = 80 ft2 or 80 square feet.
Floor and ceiling . . . (10' x 10') = 100 square feet eachFour walls . . . . . . . . (10' x 8') = 80 square feet eachTotal area inside the room = 2 (100) + 4 (80) = 520 square feet
8-ft x 10-ft = 80 square feet If you mean "20 square foot a box", then you need 4 boxes.
For simplicity sake, let's assume we have a 10 foot x 10 foot room with an 8 foot ceiling. The floor area is 10 multiplied by 10 to get 100 square feet. To get the volume multiply that by 8 and get 800 cubic feet.
Multiply 8 by 12, and get 96 square feet, as the dimension of the room.
8' x 10' = 80 square feet
10 x 8 sqft...
5 x 8 = 40 40 square feet
About 4.459 square meters.
64 square feet. Just multiply length by width - the answer is the square footage.