Q: What is the square footage of 18 ft x 4 ft pool?

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The base of the pool is a circle with a diameter of 18 ft. The radius is 9 ft. The area of the circle is (pi) times (R2) = 81pi = 254.47 square feet (rounded to 2 decimal places))

18 x 10 = 180 ft^2

To calculate square footage, you multiply the length by the width of the room. So, if the room measures 10 ft. by 18 ft., your total area is 180 sq. ft.

10*18=180sq ft

Assuming the room is 20 ft by 18 ft (the question does not say so), the area would be 20*18 = 360 square feet

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The base of the pool is a circle with a diameter of 18 ft. The radius is 9 ft. The area of the circle is (pi) times (R2) = 81pi = 254.47 square feet (rounded to 2 decimal places))

273

18 x 10 = 180 ft^2

18 ft X 20 ft = 360 Square feet

14 ft x 18 ft = 14*18 = 252 square feet.

To calculate square footage, you multiply the length by the width of the room. So, if the room measures 10 ft. by 18 ft., your total area is 180 sq. ft.

10*18=180sq ft

Assuming the room is 20 ft by 18 ft (the question does not say so), the area would be 20*18 = 360 square feet

If the floor of the pool is of uniform gradient then: Pool bottom = 18' x 36' = 648 sq ft Shallow wall = 18' x 3' = 54 sq ft Deep wall = 18' x 8' = 144 sq ft Two Sides = 2*{0.5*36*(3+8)} = 396 sq ft (they are trapezium-shaped). Total = 1242 square feet. Strictly speaking, if the pool is 36' long, the sloping length of the bottom is 36.35' (approx), so the pool bottom is 654.22 sq ft and the total is 1248.22 sq ft.

If the linear footage was measured around the whole edge of the pool the the sq ft = 689.0625 sq ft However if this is only the length of the pool then there is no way to work it out,

if you want the square footage, 15 ft x 20 ft is 300 square feet

5m * 20m = 100 m2 = 1076.4 sq ft (approx)