If the floor of the pool is of uniform gradient then:
Pool bottom = 18' x 36' = 648 sq ft
Shallow wall = 18' x 3' = 54 sq ft
Deep wall = 18' x 8' = 144 sq ft
Two Sides = 2*{0.5*36*(3+8)} = 396 sq ft (they are trapezium-shaped).
Total = 1242 square feet.
Strictly speaking, if the pool is 36' long, the sloping length of the bottom is 36.35' (approx), so the pool bottom is 654.22 sq ft and the total is 1248.22 sq ft.
The amount of DE (diatomaceous earth) needed for an 18x36 inground pool filter typically ranges from 1 to 2 pounds per square foot of the filter's surface area. To determine the exact amount, check the filter's specifications, as they often indicate the recommended DE amount. Generally, an 18x36 pool may require about 4 to 6 pounds of DE, depending on the filter model. Always consult your filter's manual for precise guidelines.
648 square feet.
18x36 = 648
To calculate the linear feet of an 18x36 pool, you need to determine the perimeter. The formula for the perimeter of a rectangle is (P = 2 \times (length + width)). For an 18x36 pool, this would be (P = 2 \times (18 + 36) = 2 \times 54 = 108) linear feet. Thus, the linear feet of the pool is 108 feet.
18 x 36 ______ 108 540 ______ 648 gallons 18x36 = 648 square feet. Assume depth of pool 5 feet filled to brim, total volume 18x36x5 = 3240 cubic feet. 3240 multiplied by 6.22883 = 20181 UK gallons (rounded) 3240 multiplied by 7.48052 = 24237 US gallons (rounded)
That will depend on how deep you want the water to be.
26700 gallons
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tile size 18X36 and 1x2 what is the covverage of a 25# bag of grout
box = 18 x 36 x 3 = 1944 cu ft wedge = 1/2 x 5 x 36 x 18 = 1620 cu ft total = 3564 cu ft = 26661 us gal
Assuming brim-full, 30x3 = 90 ft2 30x4/2= 60ft2 90+60=150ft2 150x15=2250ft3 2250ft3 = 14014.8675 UK gallons 2250ft3 = 16831.17 US gallons Answer: area on top = (18x36) ft squared = 648 ft^2 vol of top section = 648x3 = 1944ft^3 vol of (bottom) diagonal section is: 0.5(36x18).(8-3) = 1620ft^3 total vol = 1944 + 1620 = 3564ft cubed 3564 (feet cubed) = 22 199.5604 Imperial gallons what I did was split the volume of the pool into two sections and deal with them independently as two separate shapes.
Just buying a frame that size can cost up to 40 or 40 dollars. Having the poster framed would generally cost you around 100 $.