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8 x y1.5 sqrt(2)

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Q: What is the square root of 128 x2 y3?
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How do you undo exponents when different exponents are on each side of the equation?

I'm assuming that you're asking how to solve equations like this "x2 = y3", right? If you solve for x in equations such as this, you should keep in mind that y will probably have a fractional power or will be the radicand in a radical whose index isn't 2 (in other words, it won't be in a square root). You should also be conscious of the rule for converting radicals to exponents: xa/b equals the b-root of x to the a power. So, to solve x2 = y3 for x, take the square root of both sides. This results in (x2)1/2 = (y3)1/2. You know that raising a quantity to a power when addition and substraction are absent means that you have to multiply the exponents, so you would then obtain x = y3/2. Using the conversion rule, x equals the square root of y cubed. It is a square root because the denominator of the exponent of y (or "b" if you're looking at the conversion rule) is 2, but things will not always work out so nicely. I hope this helped.


What is another way to write x2 over y3?

x^2/y^3 = x^2*y^(-3)


Evaluate the expression if x2 and y3 3x plus y?

the answers is d


What is the distance formula-?

Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squaredso basically,1. find the change in x2. find the change in y3. square the change in x and the change in y(x^2) (y^2)4. add up your change in x^2 +change in y^25. fing the square root of ur answer


How do you write median median line?

the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3