I'm assuming that you're asking how to solve equations like this "x2 = y3", right? If you solve for x in equations such as this, you should keep in mind that y will probably have a fractional power or will be the radicand in a radical whose index isn't 2 (in other words, it won't be in a square root). You should also be conscious of the rule for converting radicals to exponents: xa/b equals the b-root of x to the a power. So, to solve x2 = y3 for x, take the square root of both sides. This results in (x2)1/2 = (y3)1/2. You know that raising a quantity to a power when addition and substraction are absent means that you have to multiply the exponents, so you would then obtain x = y3/2. Using the conversion rule, x equals the square root of y cubed. It is a square root because the denominator of the exponent of y (or "b" if you're looking at the conversion rule) is 2, but things will not always work out so nicely. I hope this helped.
x^2/y^3 = x^2*y^(-3)
the answers is d
Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squaredso basically,1. find the change in x2. find the change in y3. square the change in x and the change in y(x^2) (y^2)4. add up your change in x^2 +change in y^25. fing the square root of ur answer
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3
X2+Y3+15 All you can do is simplify it.
n = x2 + 1 n = y3 - 1 x2 + 1 = y3 - 1 x2 = y3 - 2 x = (y3 - 2).5 This means that you need to find all cubes where subtracting 2 yields a square: Cubes: 1, 8, 27, 64, 125,... (-2): -1, 6, 25, 62, 123,... (27,25) works. n = 26
I'm assuming that you're asking how to solve equations like this "x2 = y3", right? If you solve for x in equations such as this, you should keep in mind that y will probably have a fractional power or will be the radicand in a radical whose index isn't 2 (in other words, it won't be in a square root). You should also be conscious of the rule for converting radicals to exponents: xa/b equals the b-root of x to the a power. So, to solve x2 = y3 for x, take the square root of both sides. This results in (x2)1/2 = (y3)1/2. You know that raising a quantity to a power when addition and substraction are absent means that you have to multiply the exponents, so you would then obtain x = y3/2. Using the conversion rule, x equals the square root of y cubed. It is a square root because the denominator of the exponent of y (or "b" if you're looking at the conversion rule) is 2, but things will not always work out so nicely. I hope this helped.
x^2/y^3 = x^2*y^(-3)
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
(x2 - xy + y2)(x + y)
the answers is d
It means it is a different kind of root, such as a cubic root, which has a three above the square root symbol ('radical sign'). If y is the square root of x, it means that y2 = x. So the square root of 4 is 2, and 22 is 4. If y is the cube root of x, it means that y3 = x. So the cube root of 8 is 2, and 23 = 8.
√(49x4y6) = √49√x4√y6 = 7*x2*y3
Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squaredso basically,1. find the change in x2. find the change in y3. square the change in x and the change in y(x^2) (y^2)4. add up your change in x^2 +change in y^25. fing the square root of ur answer
Not sure. There is no particular name for x2 and 2xy (both include x) in x2 + 2xy + y2 + y3
the equation is A= y2-y2/x3-x2 after that you find the y-intercept by doing, b= y1+y2+y3-A(x1+x2+x3)/3