the square root of 17 is not a perfect square, so it can't be reduced to a rational number. √17 ≈ 4.1231 but the decimal place keeps going on forever
the square root of 17 is 4.123105625617661
Rounded to two decimal places, the square root of 17 is 4.12.
There is no square root of -289 because it is an imaginary number but the square root of 289 is 17
Not sure I understand the question. 17 is rational but the square root of 17 is irrational.
the square root of 17 is not a perfect square, so it can't be reduced to a rational number. √17 ≈ 4.1231 but the decimal place keeps going on forever
The square root of 289 is 17 since 172 or 17 * 17 = 289
the square root of 17 is 4.123105625617661
17*17 = 289 Therefore 17 is the square root of 289
The idea is to find a perfect square among its factors, such as two square, three square, etc. In this case, the square root of 68, root(68), equals root(4 x 17) = root(4) x root(17) = 2 root(17).
Rounded to two decimal places, the square root of 17 is 4.12.
There is no square root of -289 because it is an imaginary number but the square root of 289 is 17
square root of 9 = 3 but 2, 17 and 23 are irrational numbers
Not sure I understand the question. 17 is rational but the square root of 17 is irrational.
It remains as 17
The square root of 289 is ± 17.
17 plus 8 is 25, and the square root of 25 is 5. Alternatively, the square root of 17 is about 4.123; adding 8 to that gives about 12.123.