(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
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(2x - i)(2x + i)where i is the square root of negative 1.x = 0.5i, -0.5i
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: 1 plus or minus i times the square root of 2x = 2.4142135623730951ix = 0.4142135623730951iwhere i is the square root of -1
x2+2x=9 we can complete the square or use the quadratic formula. Let's complete the square. add 2/2=1 to both sides and we ahve x2+2x+1=10 now factor the left side and use the square root property (x+1)2=10 so x+1= plus of minus the square root of 10 x=- 1+ or - square root of 10 using the quadratic formula we have a=1, b=2 and c=-9 so [-2+ or - (square root of (4+36))]/2= -1 + or - square root of 10 as we had before.
The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: 1 plus or minus 7i times the square root of 1.x = 1 + 7ix = 1 - 7iwhere i is the square root of negative one.
That doesn't factor neatly. Applying the quadratic formula, we find 2 imaginary solutions: (-1 plus or minus the square root of -83) divided by 2x = -0.5 + 4.55521678957215ix = -0.5 - 4.55521678957215iwhere i is the square root of -1.
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
3
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
x2 + 2x + 5 = 0x2 + 2x + 5 - 5 = 0 - 5x2 + 2x = -5x2 + 2x + (2/2)2 = -5 + (2/2)2x2 + 2x + 12 = -5 + 1(x + 1)2 = -4sq. root of (x + 1)2 = sq. root of -4|x + 1| = 2ix + 1 = +&- 2ix + 1 - 1 = -1 +&- 2ix = -1 +&- 2i