The answer will depend on how far the square root sign goes.If you want to solve for "x", I suggest you isolate the square root on the left (if it only covers the "2x" part, move the "1" to the other side of the equation). Then, if you square both sides of the equation, you get a formula which you can easily convert to a form which can be solved with the quadratic equation.
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
It depends entirely on the value of x.
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
87
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
84
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
its 2 times 2 equals ┴¥
It depends entirely on the value of x.
x = - 4 - or + the square root of 3 Solved by using the quadratic equation formula.
87
5
If 2x2 + 3x + 9 = 0 then x = -0.75 - 1.984i or -0.75 + 1.984i where i is the imaginary square root of -1.
x = 2.
(11 plus or minus the square root of 129) divided by 4x = 5.589454172900137x = -0.0894541729001368
As written, that's 4x squared = -21 and x equals the square root of -21/4. But if you meant that to be 12x, it factors out nicely to (2x + 3)(2x + 3) and x would equal -3/2
It works out that the centre of the circle is at (-0.5, 1.5) and its diameter is the square root of 28