Between 6 and 7
6 x 6 = 36
7 x 7 = 49
The square root of 41 is approximately 6.4. The two integers that lie between the square root of 41 are 6 and 7.
It is an irrational number and lies between 6 and 7
square root of 81 is 9...and plus 32 is 41.so the answer is 41
41
41
The square root of 41 is approximately 6.4. The two integers that lie between the square root of 41 are 6 and 7.
It is an irrational number and lies between 6 and 7
the square root of 164= 2x the square root of 41
square root of 81 is 9...and plus 32 is 41.so the answer is 41
the square root of 164= 2x the square root of 41
41
It's the other way around. The square root of 41 lies between 6 and 7.
41
41
No.
The square root of 41 is an irrational , algebraic, real number. It is real, is the root of an polynomial equation with integer coefficients, but can not be expressed as a ratio of integers.
x = 41 √x = √41 √x ≈ 6.4