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sqrt(4n2) = 2n

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Q: What is the square root of 4n2?
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Related questions

Are all odd square roots the square roots of odd numbers?

Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.


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The square root of the square root of 2


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square root of (2 ) square root of (3 ) square root of (5 ) square root of (6 ) square root of (7 ) square root of (8 ) square root of (9 ) square root of (10 ) " e " " pi "


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There are infinitely many of them. They include square root of (4.41) square root of (4.42) square root of (4.43) square root of (4.44) square root of (4.45) square root of (5.3) square root of (5.762) square root of (6) square root of (6.1) square root of (6.2)


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It's not a square if it has no root. If a number is a square then, by definition, it MUST have a square root. If it did not it would not be a square.


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We use the property of square roots that says the square root of (ab)=square root (a) multiplied by square root of b So square root (4x)=square root (4) mutiplies by square root of x =2(square root (x)) 2sqrt(x)