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sqrt(4n2) = 2n

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βˆ™ 14y ago
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Q: What is the square root of 4n2?
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Related questions

Are all odd square roots the square roots of odd numbers?

Yes, they are. Sketch of proof: Odd square root is a number x of form x = 2n + 1. Square of this root is: x2=(2n+1)2=4n2+4n+1=y, which can be expressed as: y=2(2n2+2n)+1. Let t = 2n2+2n. Then, y=2t+1, which is an odd number.


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