No because the square root of 98 is 7 times the square root of 2
The simplified square root of 98 is: ±9.9 or ±10
No. If the square root of 98 was an integer, 98 would be a perfect square.
√98 ~= 9.899
49
sqrt(98) = sqrt( 2 x 49(_ = sqrt(2) X sqrt(49) = sqrt(2) X 7 usually written as 7sqrt(2) (Surd form) Numerically the answer is 9,899494937.....
No because the square root of 98 is 7 times the square root of 2
The simplified square root of 98 is: ±9.9 or ±10
The square root of 49 is 7, because 7 x 7 = 49
No. If the square root of 98 was an integer, 98 would be a perfect square.
The square root of 9604 is 98.
√98 ~= 9.899
49
49
It is 98 because 98*98 = 9604
9.899494936611665It is: 7 times square root of 2± 9.899495
2.83 to the nearest hundredth.