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The roots are (if the equation is of the form Ax2 + Bx + C = 0 ((-B) + Square Root of (B2 - 4xAxC)) / 2xA and ((-B) - Square Root of (B2 - 4xAxC)) / 2xA
(−b±√b2−4ac)÷2a the square root of b2−4ac entirely.
If it's a right triangle, a2 + b2 = c2 3 + 5 = c2 c = the square root of 8.
a2 + b2 = c2 a2 = c2 - b2 a = sqrt(c2 - b2) ==================no +/- square root as a negative length makes no sense in a right triangle
quadratics have the form ax2+bx+c=0 the discriminant is the square root of (b2-4ac) = square root of (16-16) =square root of 0 = 0