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Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)
Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)
Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)
Use Pythagoras' Theorem - the hypothenuse of a right triangle is square root of (a2 + b2)
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If you walk 5 km east then turned and walked 2 km west what would your final displacement be?
The final displacement would be 3 km east of the starting point.
Mackinzie walks 4 blocks west then 2 blocks south then 4 blocks east and finally 1 block south What is the magnitude of her total displacement during this walk in blocks?
The total is 3
Mackinzie walks 4 blocks west then 2 blocks south then 4 blocks east and finally 1 block south What is the magnitude of her total displacement during this walk?
3
If a car travels 20 meters east in 1 second would its displacement at the end of this 1 second interval be 20 m east or 20 ms east?
20ms east
What is the displacement of a hiker who travels 3.0 km east and then 4.0 km north?
5.0 km.
A girl walks 15 miles west she turns around and walks 8 miles east what is the girls distance and displacement?
She has walked 23 miles, but her displacement is only 7 miles.
A person walks 3 miles north, turns and walks 2 miles east. Calculate the persons distance traveled and their displacement?
Distance 2+3=5 displacement 2
What is the resultant displacement of someone who runs 5 miles east and 4 miles west?
5 miles minus 4 miles is 1 mile East of the starting point. Displacement is a vector quantity, so it must have magnitude and direction.
If a person walks 3 blocks East and 4 blocks North what is the displacement of the person?
5 blocks
What is the resultant displacement if a person walks 46 meters east then 23 km south?
46 squared + 23 squared = the resultant displacement squared. Pythagoras' theorem.
Sarah walks part way around around a swimming pool She walks 50 yards north then 20 yards east and 50 yards south The magnitude of her total displacement during the walk is how many yards?
Sarah's total displacement can be found using the Pythagorean theorem. The horizontal displacement is 20 yards east, and the vertical displacement is 50 yards north minus 50 yards south, which equals 0. This means her total displacement is the square root of (20^2 + 0^2) = 20 yards.
A hiker leaves camp and hikes 9 miles north and then hikes 7 miles east What is the resulting displacement of the hiker?
The resulting displacement can be found by using the Pythagorean theorem: (9 miles)^2 + (7 miles)^2 = c^2 81 + 49 = c^2 c = √130 Therefore, the resulting displacement is approximately 11.4 miles in a northeast direction.
In the process of delivering mail a postal workers walks 161 m due east from his truck he then turns around and walks 194 m due west from his truck what is the workers displacement releative to his tr?
The postal worker's displacement relative to his truck is the final position minus the initial position. In this case, it would be 194 m due west minus 161 m due east, which results in a displacement of 33 m due west.
Sara walks part way around a swimming pool She walks 50 yards north then 20 yards east then 50 yards south The magnitude of her total displacement during this walk is yards?
20
Sara walks part way around a swimming pool. She walks 50 yards north then 20 yards east then 50 yards south. The magnitude of her total displacement during this walk is yards.?
20 yards
What is the relationship between displacement and direction?
Displacement is just distance traveled and a direction. For example 40m east is a displacement distance
Sara walks part way around a swimming pool. She walks 50 yards north then 20 yards east then 50 yards south. The magnitude of her total displacement during this walk is?
The magnitude of Sara's total displacement can be found using the Pythagorean theorem. The total displacement is the square root of the sum of the squares of her displacements in each direction, which is √(50^2 + 20^2) = √(2500 + 400) = √2900 ≈ 53.85 yards.
