Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
Because the Square Root of negative 1 = i (The imaginary square root of negative 1.) and where if the square root of one number and of another number are multiplied together, the answer is equal to the square root of the two numbers combined. (Square root of 8 times the square root of 5 equals the square root of 40.) So... √(-20) =√20×√(-1) =√4×√5×i =2i(√5) The answer is 2i times the square root of 5. square root (-20) = square root (-1) x square root (20) square root (-20) = i x 4.47213595 square root (-20) = 4.47213595 i
You must be careful when multiplying square roots of negative numbers; the same rules that apply for normal square roots do NOT apply. I will use shorthand root(x) for the square root of x. For example, root(2) x root(3) = root(2 x 3) = root(6), but you can't do this with square roots of negative numbers. For example: root(-2) x root(-3) = i root(2) x i root(3) = i2 root(6) = (-1) root(6) = -root(6). "i" is the imaginary unit.
The square root of x to the seventeenth power is x to the eighth and a half power. If x is negative, the answer is imaginary.
The square root of a negative number is considered an imaginary number. In this case, the square root of -49 is 7i, where i represents the imaginary unit (√-1). This is because when you square 7i, you get -49.
Definition of Square Root: The Square Root of a number 'X' is equal to 'A' when X=A*A By definition, the square root of a positive number has two answers, one negative and one positive, that have equal magnitudes. i.e. The square roots of 4 are 2 and -2. The Non-Negative Square Root is simply asking for the positive root.
x2 actually has two square roots. One of them is indeed x. The other one is negative x.
Yes, because when x equals 1, the square root of x is rational and the square root of -x is irrational, and when x equals -1, the square root of x is irrational and the square root of -x is rational.
Because the Square Root of negative 1 = i (The imaginary square root of negative 1.) and where if the square root of one number and of another number are multiplied together, the answer is equal to the square root of the two numbers combined. (Square root of 8 times the square root of 5 equals the square root of 40.) So... √(-20) =√20×√(-1) =√4×√5×i =2i(√5) The answer is 2i times the square root of 5. square root (-20) = square root (-1) x square root (20) square root (-20) = i x 4.47213595 square root (-20) = 4.47213595 i
x=square root (-2) =i(square root of 2)WHERE i2 =-1
it is impossible to get the square root of a negative, since the definition of a square root is something times itself. example: the square root of 16 is 4 because 4 x 4 = 16. and a negative times a negative is a positive, so the square root of a negative is impossible. however, you can do the square root of 121 (which is 11) and make the 11 a negative. 11 x 11 = 121 and -11 x -11 = 121 but you could make 11 negative after the fact, if that is what you wanted to do.
You must be careful when multiplying square roots of negative numbers; the same rules that apply for normal square roots do NOT apply. I will use shorthand root(x) for the square root of x. For example, root(2) x root(3) = root(2 x 3) = root(6), but you can't do this with square roots of negative numbers. For example: root(-2) x root(-3) = i root(2) x i root(3) = i2 root(6) = (-1) root(6) = -root(6). "i" is the imaginary unit.
The square root of x to the seventeenth power is x to the eighth and a half power. If x is negative, the answer is imaginary.
The square root of a negative number is considered an imaginary number. In this case, the square root of -49 is 7i, where i represents the imaginary unit (√-1). This is because when you square 7i, you get -49.
x = 4
when x is a negative number --- is a wrong answer since square root of a negative number is not defined. So x has to be zero or a positive number. The correct answer is that when x lies between 0 and 1 (with both limits excluded), its square root is greater than the number itself. Of course at both limits, the square root (assuming the positive square root - since a square root of a number can be positive or negative, both with the same absolute value) is the same as the number.
Yes, but it involves the square root of -1. sqrt (-X) = sqrt (X) * sqrt(-1)