square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
The square root of x has two answers. It's either x (which is +x), or it's -x. If we take x times x, the answer is x2. If we take -x times -x, the answer is also x2.
x² = x+110 x²-x-110 = 0 x1= -(-1/2) - Square root of ((1/2)²+110) x1 = 0.5 - 10.5 x1 = - 10 x2 = -(-1/2) + Square root of ((1/2)²+110) x2 = 0.5 + 10.5 x2 = 11
x²-x-12=0 x1=-(-1/2) - Square root of ((-1/2)²+12) x1=0.5 - 3.5 x1=-3 x2=-(-1/2) + Square root of ((-1/2)²+12) x2=0.5 + 3.5 x2=4
x2 = 81 Square root both sides:- x = +/- 9
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
x2 square root of x is an expression, not an equation or inequality. It, therefore, has no answer.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
If you mean: 4*square root of x2 then it is 4x
sqrt(x2)=|x|, (sqrt(x))2=x*sqrt=square root of
The square root of x has two answers. It's either x (which is +x), or it's -x. If we take x times x, the answer is x2. If we take -x times -x, the answer is also x2.
5
-x times -x = x2 (negative multiplied with negative = positive) sqrt of x2 = x
x2-b = 9 x2 = 9+b Square root both sides: x = the square root of (9+b)
x2 - 1 is not a perfect square and thus does not have a square root. It does have two factors though, and those would be (x - 1) and (x + 1). *** if x2-1 is in the square root symbol [also (x2-1)-2 ], you would end up with x+1-2 throught the process of distribution. (which is the same as saying the square root of 1)
Yes. For example, the equation x2 = 2, which in standard form is x2 - 2 = 0, has the two solutions x = square root of 2, and x = minus square root of 2.
the integral of the square-root of (x-1)2 = x2/2 - x + C