If you mean: 4*square root of x2 then it is 4x
The square root of 16 is four. Four cubed is 4 x 4 x 4 = 64
Take out the largest perfect square you can find, in this case, 4: root(40) = root(4 x 10) = root(4) x root(10) = 2 x root(10).
3/(4*square root(x)) ....Mukesh
x2 + 4 = 0 then get the x on one side. x2 = -4 then find the square root of both which would cancel the square on the x. therefore the answer is: x = the square root of -4 = i squared root 4, which is a complex number ( imaginary number) since you cannot find the square root of oa negative number
4
The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).The idea is to take any perfect square out of the square root sign. root(24) = root(4 x 6) = root(4) x root(6) = 2 x root(6).
square root is 8 (8 x 8 = 64)cube root is 4 (4 x 4 x 4 = 64)
Square root of 56 = Square root of (4 x 14) = (Square root of 4) x (Square root of 14) = 2 x (Square root of 14) The actual value would be 2 x 3.741 = 7.482
4 x square root of 10 minus square root of 10 = 3 x square root of 10.
If you mean: 4*square root of x2 then it is 4x
If x is a multiplication symbol, then square root of 36(4)y^2 = square root of(4^2)(2^2)(y^2) = (4)(2)(y) = 8y If it is a variable x, then square root of 36x4y^2 = square root of (4^2)(x)(2^2)(y^2) = (4)(2)(y)(square root of x)= 8y(square root of x)
Yes.
the square root of x*x is x if there is a 3 then a square root it is acutally cube root. the cube root of x*x*x is x if there is a 4 then a check symbol then that is fourth root. the fourth root of x*x*x*x is x. the square root of 16 is 4(4*4=16). the fourth root of 16 is 2(2*2*2*2=16).
x plus the square root of 2
Square root of 324 = square root of (81 x 4) = square root of 81 x square root of 4 and that is 9 x 2 = 18 cm
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2