answersLogoWhite

0

Yes.

User Avatar

Wiki User

14y ago

What else can I help you with?

Related Questions

What is the square root of a square root?

It is called the fourth root, and is denoted x1/4 or x0.25 (as opposed to x1/2 and x0.5 for square roots). It can also be denoted 4√x. A square root of a square root is the fourth root of a number.


What is a square root of a square root?

It is called the fourth root, and is denoted x1/4 or x0.25 (as opposed to x1/2 and x0.5 for square roots). It can also be denoted 4√x. A square root of a square root is the fourth root of a number.


How are fractional exponents and radicals are related?

Here are some examples. x1/2 = square root of x; x1/3 = cubic root of x; in general, x1/n = nth root of x. Also, x2/3 = the square of the cubic root of x, or equivalently, the cubic root of the square of x.


X2 plus 8x-5 equals 0?

if you mean X²+8X-5=0: X1=-8/2 - Square root of ((8/2)²+5) X1=-4 - Square root of 21 X1 is about -8.58 X2=-8/2 + Square root of ((8/2)²+5) X2=-4 + Square root of 21 X2 is about 0.58


What is the derivative of the square root x?

Use: √x = x1/2 By the Power Rule (Decrease the power by 1. Multiply by the original power.): d/dx √x = d/dx x1/2 = 1/2 x-1/2


How do you find distance between two points?

If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).If you know the coordinates, use the Pythagorean Theorem: take the square root of ((x2 - x1)2 + (y2 - y1)2).


What is the distance between the points -2 0 and 5 3?

Let (x1, y1) = (-2, 0) and (x2, y2) = (5, 3). Distance between two points = square root of [(x2 - x1)2 + (y2 - y1)2] = square root of [(5 - -2)2 + (3 - 0)2] = square root of (72 + 32) = square root of 58


Find dydxsquare root x?

Write square root of x as x1/2. Then use the formula for the derivative of a power.


The distance between points x1 y1 and 5 -5 is the square root of x1 plus 5 2 plus y1 - 52?

false


X2 - x - 12 equals 0?

x²-x-12=0 x1=-(-1/2) - Square root of ((-1/2)²+12) x1=0.5 - 3.5 x1=-3 x2=-(-1/2) + Square root of ((-1/2)²+12) x2=0.5 + 3.5 x2=4


How do you convert the square root of x into an expression?

Write it as sqrt(x) or x1/2 or x0.5


X2 plus 2x - 15 equals 0?

x²+2x-15=0 x1=-2/2 - Square root of ((2/2)²+15) x1=-1-4 x1=-5 x2=-2/2 + Square root of ((2/2)²+15) x2=-1+4 x2=3