six on the square root of three
The square root of 9 is 3 which is a rational number
1.7724538509......
1000
19
8
11.1803398
39.68626967
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618
35.805
the diagnol is the side of the square times squareroot(2) so the length of the side is 11/squareroot(2) and in simplified form your final answer is 11*squareroot(2)/2
29 29X29=841