The standard deviation of 2 3 5 6 = 1.8257
For 1 2 2 3 4 5 5 5 5 6: σ=1.6865
2√(17/21), or about 1.8.
To have a mean of 5 and a standard deviation of 1, a set of numbers can be constructed such that the average of the numbers equals 5, while their spread from that average is consistent with a standard deviation of 1. For example, the numbers 4, 5, and 6 meet these criteria: their mean is (4 + 5 + 6) / 3 = 5, and the standard deviation is calculated to be 1. Other combinations of numbers can also satisfy these conditions, as long as they maintain the same mean and standard deviation.
Consider thatxd= x- Arithmetic meand211-1.5 = -0.50.2522-1.5 = 0.50.25=0.5Arithmetic mean = (1+2)/2 =1.5Standard deviation=ie .5= 0.70now Considerxd= x- Arithmetic meand211-2=-1122-2=0033-2=11Arithmetic mean= (1+2+3)/3 = 2 =2Standard deviation= = (2/2) = 1So the Standard deviation can increasenow Considerxd= x- Arithmetic meand211-1.25=-0.250.062522-1.25=0.750.562511-1.25=-0.250.062511-1.25=-0.250.0625Arithmetic mean= (1+2+1+1)/4= 1.25 = .75Standard deviation= = (0.75/4) = 0.4330So the Standard deviation can decreaseStandard deviation can either decrese or increase or remains the same
For 3 5 8 7 2 4 6: σ=2.1602
From the online calculator, see related link, the standard deviation is 4.06202.
The standard deviation of 2 3 5 6 = 1.8257
It would be 3*5 = 15.
1. establishment of standard 2. fixation of the standard 3. compairing actual performance with standard performance 4. finding out the deviation 5. correcting the deviation
For 1 2 2 3 4 5 5 5 5 6: σ=1.6865
σ=2.49
2√(17/21), or about 1.8.
To have a mean of 5 and a standard deviation of 1, a set of numbers can be constructed such that the average of the numbers equals 5, while their spread from that average is consistent with a standard deviation of 1. For example, the numbers 4, 5, and 6 meet these criteria: their mean is (4 + 5 + 6) / 3 = 5, and the standard deviation is calculated to be 1. Other combinations of numbers can also satisfy these conditions, as long as they maintain the same mean and standard deviation.
You can calculate standard deviation by addin the numbers of data that are together and dividing that number by the amount pieces of data.THAT IS TOTALLY INCORRECT.What was answered above was the calculation for getting an (mean) average.If you take five numbers for example 1, 2, 3, 4, 5 then the (mean) average is 3.But the standard deviation between them is 1.58814 and the variance is 2.5Also the population std. deviation will be 1.41421 and the population variance will be 2.see standard-deviation.appspot.com/
Any real value >= 0.
Absolute deviation from what?
Consider thatxd= x- Arithmetic meand211-1.5 = -0.50.2522-1.5 = 0.50.25=0.5Arithmetic mean = (1+2)/2 =1.5Standard deviation=ie .5= 0.70now Considerxd= x- Arithmetic meand211-2=-1122-2=0033-2=11Arithmetic mean= (1+2+3)/3 = 2 =2Standard deviation= = (2/2) = 1So the Standard deviation can increasenow Considerxd= x- Arithmetic meand211-1.25=-0.250.062522-1.25=0.750.562511-1.25=-0.250.062511-1.25=-0.250.0625Arithmetic mean= (1+2+1+1)/4= 1.25 = .75Standard deviation= = (0.75/4) = 0.4330So the Standard deviation can decreaseStandard deviation can either decrese or increase or remains the same