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Without an equality sign the given terms can't be considered to be an equation.

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The vertex form of the equation of a parabola is y x-5 2 plus 16 what is the standard form of the equation?

In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.


What is the standard form of 13 equals 4x plus 5y?

The standard form, which is the form that can be generalised to 3 or more dimensional spaces, is 4x + 5y - 13 = 0


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The simple form of the equation 5 - 9 + (-1) is -5.


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Solve the equation x plus 13 equals -8?

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In the equation 3x plus 7 equals 13, x is equal to 2.


How do you solve the equation x2 plus 12x plus 13?

An equation demonstrates the equality of two expressions. x2+12x+13 is only one expression. For example, x+y : expression, not equation x+5 = 3 : equation


How do you write 13 and 223 thousandths in standard form?

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What is the equivalent of the following equation y equals x2 - 8x plus 29?

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Where does x equals 9-2y and x plus 2y equals 13 intersect on a graph?

first get both your equations into standard form... x + 2y = 9 (equation 1) x + 2y = 13 (equation 2) multiply equation 1 by (-1) -x - 2y = -9 x + 2y = 13 add the equations together 0 + 0 = 4 0 = 4 since the equations dont equal out then these equations do not intersect and are therefore parallel. PARALLEL is your answer


What is the vertex of the parabola y equals -2x squared plus 12x -13?

There are two forms in which a quadratic equation can be written: general form, which is ax2 + bx + c, and standard form, which is a(x - q)2 + p. In standard form, the vertex is (q, p). So to find the vertex, simply convert general form into standard form.The formula often used to convert between these two forms is:ax2 + bx + c = a(x + b/2a)2 + c - b2/4aSubstitute the variables:-2x2 + 12x - 13 = -2(x + 12/-4)2 -13 + 122/-8-2x2 + 12x - 13 = -2(x - 3)2 + 5Since the co-ordinates of the vertex are equal to (q, p), the vertex of the parabola defined by the equation y = -2x2 + 12x - 13 is located at point (3, 5)