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The mean of eight numbers is 41. The mean of two numbers is 29. What is the mean of the other six numbers?

45


Are 131741 prime numbers?

If you mean 13, 17 and 41 then they are all prime numbers


Which of these are prime numbers 2 10 13 21 41 50 69 83?

13, 41, 83


What is the answer to this question and how do you get to it. The mean of eight numbers is 41 and the mean of two of the numbers is 29 what is the mean of the other 6 numbers?

Work with the total sums of the numbers:The mean of eight numbers is 41, so the total of those eight numbers is 8 x 41 = 328The mean of two of those eight numbers is 29, so the total of those two numbers is 2 x 29 = 58So the total of the other six numbers must be the difference between these two totals, that is 328 - 58 = 270Thus the mean of these six numbers is their total divided by 6, namely 270 ÷ 6 = 45.


What is the mean of these numbers 41 47 49 50 44?

46.2


What is the sum of all prime numbers between 10 and 16?

The sum of all prime numbers between 10 and 16 is 41.


What is 4 into 41?

Its positional place value is 40 = forty or if you mean 41/4 then it is 10 remainder 1


What formula yields prime numbers?

x^2 - x + 41 = these are for 5, 7, 10... after 40 they become composite with this equation 5^2 - 5 + 41 = 61 (Prime) 7^2 - 7 + 41 = 83 (Prime) 10^2 - 10 + 41 = 131 (Prime)


Which of these numbers are composite 53 81 41 47 31?

If you mean: 53 81 41 47 and 31 then 81 is a composite number while all the rest are prime numbers


Which numbers from 41 to 50 are prime numbers?

41, 43, 47


How this numbers 41 59 83 23 31 round them to the nearest multiple of 10?

82


What pair of numbers have the LCM of 12?

6 and 12