-61
To find the probability of rolling a sum of six followed by a sum of eight with two six-sided dice, we first calculate each individual probability. The probability of rolling a sum of six is 5/36, and the probability of rolling a sum of eight is 5/36 as well. Since these events are independent, we multiply the probabilities: (5/36) * (5/36) = 25/1296. Thus, the probability of rolling a sum of six followed by a sum of eight is 25/1296.
The smaller number is "5". 5x5=25 6x6=36 25+36=61
The sum of 120 and 36 is 156.
Only 25 which is, 52 = 32 + 42 (25 = 9 + 16)
4, 5 & 6 (16 + 25 + 36)
To find the probability of rolling a sum of six followed by a sum of eight with two six-sided dice, we first calculate each individual probability. The probability of rolling a sum of six is 5/36, and the probability of rolling a sum of eight is 5/36 as well. Since these events are independent, we multiply the probabilities: (5/36) * (5/36) = 25/1296. Thus, the probability of rolling a sum of six followed by a sum of eight is 25/1296.
25 and 11
The smaller number is "5". 5x5=25 6x6=36 25+36=61
The sum of 120 and 36 is 156.
The sum of 52 and 36 is 88.
Only 25 which is, 52 = 32 + 42 (25 = 9 + 16)
25+36=61 is that what you want to hear?
The sum of 4/9 and 1/4 is 25/36.
925
4, 5 & 6 (16 + 25 + 36)
Sum of divisors = 91.
36