Only 25 which is, 52 = 32 + 42 (25 = 9 + 16)
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
25 = 9 + 16 There are many more sets like these. This one has the smallest numbers.
no
64 and 36.
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
25 = 9 + 16 There are many more sets like these. This one has the smallest numbers.
The only squares of perfect squares in that range are 1, 16, and 81.
no
64 and 36.
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
Sum of squares? Product?
sum of squares: 32 + 52 = 9 + 25 = 34 square of sum (3 + 5)2 = 82 = 64 This is a version of the Cauchy-Schwarz inequality.
The proposition in the question is simply not true so there can be no answer!For example, if given the integer 6:there are no two perfect squares whose sum is 6,there are no two perfect squares whose difference is 6,there are no two perfect squares whose product is 6,there are no two perfect squares whose quotient is 6.
split 10 in two parts such that sum of their squares is 52. answer in full formula
Since the last digit of 5077 is 7, the last digit of the perfect square numbers must be 1 and 6. So that we have 5077 = 712 + 62.
There is no simplification nor factorisation of a sum of two squares.