3 and 7.
11 and 10
-21 has four factor pairs. (21,-1)(-21,1)(7,-3)(-7,3) None of them have a sum of -8.
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
1
31
3 and 7.
The product of 3 and 7 is found by multiplying the two numbers together, which equals 21. The sum of 3 and 7 is found by adding the two numbers together, which equals 10. Therefore, the difference between the product of 3 and 7 and the sum of 3 and 7 is 21 - 10 = 11.
3 and 7 are the prime numbers because they cannot be divided by any number other than themselves and 1because 3+7 = 10 (Sum)and 3x7 = 21 (Product)
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
Three and Seven
11 and 10
10 and 11
11 and 10
10 and 11
3 (21+5)
7x + 10