Q: What is the factorization of x2 plus 10x plus 21?

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x2 + 10x + 21 = (x + 3)(x + 7)

(x2+10x+21)/(x+3) = (x+7)

Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!

x2+10x+21 = (x+3)(x+7) when factored.....

x2+10x-24 = (x-2)(x+12) when factored

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x2 + 10x + 21 = (x + 3)(x + 7)

(x2+10x+21)/(x+3) = (x+7)

x2+10x+21 = (x+3)(x+7)

Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!

(x-7)(x-3)

x2+10x-336

x2+10x+21 = (x+3)(x+7) when factored.....

x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10

If that's + 10x + 21, the answer is (x + 7)(x + 3)

x2+10x-24 = (x-2)(x+12) when factored

X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16

x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.