Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
5(8 + 5)
5 squared = 25 8 squared = 64 64+25=89
8 and 17
25 and 33
It is: 7+8+25 = 40
The two numbers with a sum of 33 and a product of 200 are 25 and 8. 25 x 8 = 200, 25 + 8 = 33.
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
21
5(8 + 5)
5 squared = 25 8 squared = 64 64+25=89
8 and 17
25 and 33
The two numbers are 5 & 3 5*5=25 3*3=9 25+9=34 5+3=8
Sum of first 25 multiples of 44+8+12....100taking 4 common4(1+2+3+4....+25) = 4*325 =1300
5^2 - (5 + 8) 25 - 13 12
sum = 1/2 x number_of_terms x (first + last) number_of_terms = (last - first) ÷ difference + 1 = (25 - 0.5) ÷ 3.5 + 1 = 8 ⇒ sum = 1/2 x 8 x (0.5 + 25) = 102