Sum of first 25 multiples of 4
4+8+12....100
taking 4 common
4(1+2+3+4....+25) = 4*325 =1300
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5 + 10+15+20=50 ans
To find the sum of the first 4 multiples of 6, you can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, the first 4 multiples of 6 are 6, 12, 18, and 24. Plugging these values into the formula, you get Sn = 4/2 * (6 + 24) = 2 * 30 = 60. Therefore, the sum of the first 4 multiples of 6 is 60.
To find the sum of the first 100 positive multiples of 4, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum, n is the number of terms, a1 is the first term, and an is the last term. In this case, a1 = 4, an = 4*100 = 400, and n = 100. Plugging these values into the formula, we get: Sn = 100/2 * (4 + 400) = 50 * 404 = 20,200. Therefore, the sum of the first 100 positive multiples of 4 is 20,200.
Multiples are not 5, 10, 15 20, 25. WRONG! It means like 1. Because, 1x25= 25. Therefore it is a multiple. 2x nothing= 25. 5x5= 25 MULTIPLE!
the multiples of 4 are 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60 those are the multiples of 4