If average for 3 = 84 then sum for 3 = 84*3 = 252. If average for 4 = 88 then sum for 4 = 88*4 = 352 so required score in quiz 4 = 100.
The sum of 622 and 84 is 706.
-3
If two prime number have a sum of 54 they cannot have a sum of 84, and conversely.
Mean = sum/count = 302/4 = 75.5
The factors of -84 that equal the sum of -16 are: -28 and 12 -14 and -2 -12 and -4
If average for 3 = 84 then sum for 3 = 84*3 = 252. If average for 4 = 88 then sum for 4 = 88*4 = 352 so required score in quiz 4 = 100.
The sum of 622 and 84 is 706.
40 + 44 = (10 x 4) + ( 11 x 4) = 21 x 4 = 84
-3
In the problem 56 + 28 = 84, 84 is the sum.
If two prime number have a sum of 54 they cannot have a sum of 84, and conversely.
82, 84, 86, 88
Mean = sum/count = 302/4 = 75.5
40 + 44 = (4 x 10) + (4 x 11) = 4 x 21 = 84
81 + 1 + 1 + 1
36/48