It is: 5 + 3 - - 12+12 = 32
12 x 5 = 60
3*4*5=60 3+4+5=12
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
The sum of the prime numbers from 1 to 12 is equal to 2 + 3 + 5 + 7 + 11 = 28.
The numbers are 3, 4 and 5.
12 x 5 = 60
The sum of 5/12 and 2/3 is 1 1/12The sum of 5/12 and 2/3 is 1 1/12
The sum of 1/6 and 1/4 is 5/12
3*4*5=60 3+4+5=12
The product of 4 and 3 is (4 \times 3 = 12). The sum of 4 and 3 is (4 + 3 = 7). To find how much greater the product is than the sum, we subtract the sum from the product: (12 - 7 = 5). Therefore, the product is 5 greater than the sum.
The sum of the prime numbers from 1 to 12 is equal to 2 + 3 + 5 + 7 + 11 = 28.
2 + 3 = 5
the sum would be 1/4 + 3/5 = 5/20 + 12/20 = 17/20
9
7/3 +5/3=12/3=4
The sum of 7 and 5 is 12
To calculate the sum, first find 4 of 6 of 12, which is ( \frac{4}{6} \times 12 = 8 ). Next, find 3 of 5 of 15, which is ( \frac{3}{5} \times 15 = 9 ). Finally, adding these together gives ( 8 + 9 = 17 ). Thus, the sum is 17.