Wiki User
∙ 13y ago41
Wiki User
∙ 13y agoSum = 79*(79+1)/2 = 79*80/2 = 3160
256 + 112 = 368, however if you meant what is the sum of 2,5,6 + 1,1,2, then that would be 13 (2+5+6) + 4 (1,1,2) = 17.
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1
If you mean: (x+3)^2 = (x+2)^2 +13 Then the value of the number x works out as 4
This is a false statement. An example would be 1/3 plus 3/4; the sum of wich is 13/12 or 1 1/12.
The sum of 23 and 13 is 36
The sum of 8 1/2 and 4 1/2 is 13.
if (n%2==0) sum=n/2*(n+1); else sum=(n+1)/2*n;
Sum = 79*(79+1)/2 = 79*80/2 = 3160
2
2
The sum of 2/3 and 1/5 is 13/15.
The sum of 2/5 and 8/9 is 1 13/45
256 + 112 = 368, however if you meant what is the sum of 2,5,6 + 1,1,2, then that would be 13 (2+5+6) + 4 (1,1,2) = 17.
4
(1/2) + (1/3) = (3/6) + (2/6) = 5/6
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1