Q: What is the sum of 66 and 17?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

The numbers are -18, -17, -16 and -15.

Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.

66

a + b = 50 a - b = 16 2a = 66 a = 33 b = 17

The sum of 17 and 75 is 92.

Related questions

83

11 and 6 11+6 = 17 11*6 = 66

66.

66 is a single number and so there is no sum as such. The only value is 66.

The numbers are -18, -17, -16 and -15.

Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.

The sum is 28+38 = 66

66

66

a + b = 50 a - b = 16 2a = 66 a = 33 b = 17

The sum of 17 and 75 is 92.

66