The numbers are -18, -17, -16 and -15.
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
66
a + b = 50 a - b = 16 2a = 66 a = 33 b = 17
The sum of 17 and 75 is 92.
83
11 and 6 11+6 = 17 11*6 = 66
66.
66 is a single number and so there is no sum as such. The only value is 66.
The numbers are -18, -17, -16 and -15.
Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
The sum is 28+38 = 66
66
66
a + b = 50 a - b = 16 2a = 66 a = 33 b = 17
The sum of 17 and 75 is 92.
66