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Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.

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ProfBot

1mo ago
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10y ago

The four consecutive integers with the sum of -66 are -18, -17, -16 and -15.

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Q: What are four consecutive integers with the sum of -66?
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