Let's denote the four consecutive integers as n, n+1, n+2, and n+3. The sum of these integers can be represented as n + (n+1) + (n+2) + (n+3) = 4n + 6. Given that the sum is -66, we can set up the equation 4n + 6 = -66. Solving for n, we find that n = -18. Therefore, the four consecutive integers are -18, -17, -16, and -15.
The numbers are -18, -17, -16 and -15.
It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.
The numbers are 21, 22 and 23.
65, 66, 67
x+(x+2)= 66.
21, 22, 23
64 65 66 67
The numbers are -18, -17, -16 and -15.
The average of three numbers which sum to 66 is 66/3 = 22. If 22 is the sum of three consecutive integers, then those three integers are 21,22,23. Kermit Rose
The numbers are -23, -22, and -21.
201
It's an imaginary number, one that exists only in fiction, if the author wants it to. There are no two consecutive integers whose sum is 66. 32 + 33 = 65 33 + 34 = 67 The sum of two consecutive integers is always an odd number.
The numbers are 21, 22 and 23.
65, 66, 67
They are 64, 65 and 66 as well as a set of consecutive odd integers: 63, 65 and 67.
-66 and -68
66