27 is the sum : 4 + 6+ 8 + 9 = 27
Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
It could be: (4*8)+(9-6) = 35
The sum of 1/6 and 4/9 is 11/18.
It is the equation 9x + 6 = 4
27 is the sum : 4 + 6+ 8 + 9 = 27
Sum = 42 Count = 6 Mean = Sum/Count = 42/6 = 7
Sum = 24 Count = 4 Mean = Sum/Count = 24/4 = 6
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
It could be: (4*8)+(9-6) = 35
The sum of 1/6 and 4/9 is 11/18.
It is the equation 9x + 6 = 4
(9 + 15)/(-5 + 1) = 24/-4 = -6.
The sum of 5/6 and 4/9 is 1 5/18
9x + 6 = 2 9x = -4 x = -4/9
A sum of 9 with 2 dice can be achieved with 3+6, 4+5, 5+4, and 6+3, so there are 4 elements in the event space for a sum of 9. This corresponds to a probability of 4 in 36, or 1 in 9, or about 0.1111 for that result.
There are 36 permutations of rolling two dice. Of these, 9 of them result in a sum of 9 or greater, specifically 6-3, 6-4, 6-5, 6-6, 5-4, 5-6, 4-5, 4-6, and 3-6. The probability, then, of rolling a sum greater than 8 on a pair of fair dice is 9 in 36, or 1 in 4, or 0.25.