A "sum" is a process that involves at least two numbers, and a "product" is also
a process that involves at least two numbers.
Your question talks about a 'sum' and a 'product', so we expect to find at least four
numbers to work with. But there are only two numbers in the whole question. So, to
put it gently, we find the question to be somewhat deficient, and lacking an answer.
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
The two numbers that have a product of 64 and a sum of 16 are 8 and 8. Since both numbers are the same, their product is (8 \times 8 = 64) and their sum is (8 + 8 = 16).
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
6 and 2 are a number pair with a sum of 8 and a product of 12
Write a pair of number which have a sum of 11 and a product of 24?
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
The sum of 8 and 5 is 13. There is then no number with which to calculate its product.
8
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
(8*4) + (8-4) = 32 + 4 = 36 ^ ^ sum ^ product and difference
6 and 2 are a number pair with a sum of 8 and a product of 12
The nos. Are 8 and -8 Sum of the nos. 8+(-8)=0 Product of the nos. 8 × (-8) = -64
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
Write a pair of number which have a sum of 11 and a product of 24?
65
-8 and -3 have a sum of -11 and product of 24
find the sum and product of the roots of 8×2+4×+5=0