The only arithmetic mean of 7 and 25 is (7+25)/2 =16. If you really mean all arithmetic means of all possible pairs of numbers between 7 and 25, then there are so many pairs you should clearly state so in your question. Or better still, just write them down, work them out and add them up, which is what I would have to do.
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.
Add all the data together and then divide the sum by the number of data points. For example, 3, 4, 5, 6, 7 Sum is 25 There are 5 numbers or data points which combined to make that sum The mean or arithmetic average is 25/5 = 5
Assuming the series is 1 + 3 + 5 + ... + 25, the answer is 169.
The only arithmetic mean of 7 and 25 is (7+25)/2 =16. If you really mean all arithmetic means of all possible pairs of numbers between 7 and 25, then there are so many pairs you should clearly state so in your question. Or better still, just write them down, work them out and add them up, which is what I would have to do.
By using the formula for an arithmetic series. This is basically obtained by reasoning: The sum of the first 25 numbers is the same as 25 multiplied by the average of those numbers; the average in this case is simply (1 + 25) / 2.
The median of 25 and 50 is also their arithmetic mean. 37.5
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.
I assume the question refer to the sum of positive odd numbers up to 25. If so, the answer is 169. If not, please resubmit your question stating exactly what you require.
Add all the data together and then divide the sum by the number of data points. For example, 3, 4, 5, 6, 7 Sum is 25 There are 5 numbers or data points which combined to make that sum The mean or arithmetic average is 25/5 = 5
Assuming the series is 1 + 3 + 5 + ... + 25, the answer is 169.
The sum of all integers between 1 and 25 is equal to (25 x (25 - 1))/2 = 325.
sum = 1/2 x number_of_terms x (first + last) number_of_terms = (last - first) ÷ difference + 1 = (25 - 0.5) ÷ 3.5 + 1 = 8 ⇒ sum = 1/2 x 8 x (0.5 + 25) = 102
The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325