The only arithmetic mean of 7 and 25 is (7+25)/2 =16. If you really mean all arithmetic means of all possible pairs of numbers between 7 and 25, then there are so many pairs you should clearly state so in your question. Or better still, just write them down, work them out and add them up, which is what I would have to do.
16
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
The sum of all integers between 1 and 25 is equal to (25 x (25 - 1))/2 = 325.
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
There are 12 even numbers between 2 and 24 inclusive.The sum is 154.
16
Factors of 25: 1, 5, 25 Their sum = 31 Difference between 31 and 8 = 23.
The sum of all integers between 1 and 25 is equal to (25 x (25 - 1))/2 = 325.
The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.
There is a formula to calculate this sum. It is, S = ½n(n + 1) In this question, n = 25 so the sum of the numbers from 1-25 is, ½ x 25 x 26 = 325
3665, excluding 25 and 100.
The sum of prime numbers between 1 and 25 is 100. 2 + 3 + 5 + 7 + 11 +13 +17 + 19 + 23 = 100
the sum of all whole numbers between 247,001 and 247,140 that can be divided exactly by 25 is 3,459,987.
The numbers are 24, 25, 26, 27, 28 and their sum is 130
There are 12 even numbers between 2 and 24 inclusive.The sum is 154.
Two, whose digital sum is 5.
34