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What is the sum of the digits of 10?
The sum of the digits of the number 10 is calculated by adding its individual digits together. The digits in 10 are 1 and 0. Therefore, the sum is 1 + 0 = 1.
Number whose sum of digits is 10?
There are many numbers whose digits sum to 10, such as 19, 28, and 37. For instance, in the number 28, the digits 2 and 8 add up to 10. Similarly, the number 55 has digits that also sum to 10 (5 + 5). Any combination of digits that meets this criterion can represent such a number.
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
When you divide my number by 5 the remainder is 4 my number has two digits and both digits are even the sum of the digits is 10?
64
What number is coMposite has 6 factors and the sum of the digits is 10?
28
What is the sum of the digits of 10?
The sum of the digits of the number 10 is calculated by adding its individual digits together. The digits in 10 are 1 and 0. Therefore, the sum is 1 + 0 = 1.
When do you need to regroup in a addition problem?
When the sum of the digits you are adding is 10 or larger.
What is the maximum value of the sum of the digits of the sum of the digits of a three-digit number?
10 9+9+1 = 19 1+9=10
Algorithm for to find sum of individual digits of a positive integer?
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
How you have 28 in number is 20 and 32.The sum of the digits is 10?
The number 28 is a perfectly reasonable number. The sum of the digits of several numbers is 10. 19 for instance
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
Program in c language to find the sum of digits?
#include <stdio.h> void main() { int digi,num,i,sum=0; printf("Enter the number of digits:"); scanf("%d",&num); while(i>0); { for(i=0;i<10000;i++) { digi=num; i=digi%10; sum=sum+i; num=digi/10; } printf("The sum of digits entered is %d",sum); } }
What is the smallest two digit number that can be divided by its own digits?
By the sum of its digits: 10. By each of its individual digits: 11.
Program in c language to find sum of digits using recursion?
# includevoid main(){int no,rem=0,sum=0,n; /*declaration*/printf("Enter 2 digit number:");scanf("%d",&no);for(n=1;n
When you divide my number by 5 the remainder is 4 my number has two digits and both digits are even the sum of the digits is 10?
64
When you divide the number by 5 the remainder is 4 the number has 2 digits and both digits are even the sum of the digits is 10?
64
How many digits have the sum of 5 between 10 and 30?
3
