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What is the sum of digits of 10?
1+0 = 1
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
When you divide my number by 5 the remainder is 4 my number has two digits and both digits are even the sum of the digits is 10?
64
What number is coMposite has 6 factors and the sum of the digits is 10?
28
Write a java program to find out the sum of a number of n digits?
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
When do you need to regroup in a addition problem?
When the sum of the digits you are adding is 10 or larger.
What is the maximum value of the sum of the digits of the sum of the digits of a three-digit number?
10 9+9+1 = 19 1+9=10
Algorithm for to find sum of individual digits of a positive integer?
enter the number whose digits are to be added num is the given value num=0! k=num%10 sum=sum=k k=num/10 num=k print the sum of the digits
What is the sum of digits of 10?
1+0 = 1
How you have 28 in number is 20 and 32.The sum of the digits is 10?
The number 28 is a perfectly reasonable number. The sum of the digits of several numbers is 10. 19 for instance
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
Program in c language to find the sum of digits?
#include <stdio.h> void main() { int digi,num,i,sum=0; printf("Enter the number of digits:"); scanf("%d",&num); while(i>0); { for(i=0;i<10000;i++) { digi=num; i=digi%10; sum=sum+i; num=digi/10; } printf("The sum of digits entered is %d",sum); } }
Between 41 and 47 and the sum of the digits is 10?
41.542.443.344.245.146
What is the smallest two digit number that can be divided by its own digits?
By the sum of its digits: 10. By each of its individual digits: 11.
Program in c language to find sum of digits using recursion?
# includevoid main(){int no,rem=0,sum=0,n; /*declaration*/printf("Enter 2 digit number:");scanf("%d",&no);for(n=1;n
When you divide the number by 5 the remainder is 4 the number has 2 digits and both digits are even the sum of the digits is 10?
64
When you divide my number by 5 the remainder is 4 my number has two digits and both digits are even the sum of the digits is 10?
64
