The sum of the first 10 natural numbers is 51.
The sum of the first 57 natural numbers is 1,625.
The sum of the first 10 natural numbers is 51, with an average of 5.1
Here it is: 500,001
To find the algorithm for the sum of the first five natural numbers, you can use the formula ( S_n = \frac{n(n + 1)}{2} ), where ( n ) is the number of terms. For the first five natural numbers, plug in ( n = 5 ): ( S_5 = \frac{5(5 + 1)}{2} = \frac{5 \times 6}{2} = 15 ). Thus, the sum of the first five natural numbers is 15. Alternatively, you could also simply add them directly: ( 1 + 2 + 3 + 4 + 5 = 15 ).
#include<stdio.h> int main() { int limit,num,sum=0,i; printf("enter a number"); scanf("%d",&num); for(i=0;i<=num;i++) sum+=i; printf("%d",sum); return 0; }
The sum of the first 57 natural numbers is 1,625.
Find the sum of the first hundred even natural number divisible by 5?
The sum of the first 100 natural numbers is 5,001.
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Write an. Algorthim. To. Find the. Sum. Of. First15 natural. Numbers
The sum of the first 10 natural numbers is 51, with an average of 5.1
Here it is: 500,001
Sum = Sum + first number Sum = Sum + second number Sum = Sum + third number Average = 1/3 x Sum
Yes
= The sum of two numbers is -42 the first number minus the second number is 52 Find the numbers? =
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
Formula for sum of first natural number = n(n+1)/2 , here n=225 so, answer is 225(225+1)/2 = 25425