The sum of q and 8 can be represented as q + 8. This is a simple algebraic expression where q is a variable representing an unknown value. Adding 8 to q means combining the value of q with 8 to get the sum.
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
18 and 1
17
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
q+8
The sum of q and 8 can be represented as q + 8. This is a simple algebraic expression where q is a variable representing an unknown value. Adding 8 to q means combining the value of q with 8 to get the sum.
The expression is simply: 9+q
The sum of a number x and 84
The sum of 1 + 8 is 9.
Only if all the suits are the same for the 9 10 Q Q K combo and all the suits are not the same on the 9 9 8 8 K combo - in that case, you'd have a straight. Otherwise, no - 9 10 Q Q K is only one pair, whereas 9 9 8 8 K is two pair.
The sum of 8, 11 and 9 is 28.
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.
18 and 1
17
The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }