360o
360 degrees
540o = 6 right angles so 5 sides (interior angles of any polygon = (2 x sides - 4) right angles.
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
Sum of angles in a polygon is (n -2)180. Hexagon has six sides. So the sum of angles is (6- 2)180. (4)180 =720
Sum of interior angles of a polygon = (2n - 4)right angles 1260 = (2n - 4) x 90 1260 = 180n - 360 900 = 180n n = 5, it is a pentagon
360 degrees
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.
(2n - 4) right angles where n is the number of sides.
540o = 6 right angles so 5 sides (interior angles of any polygon = (2 x sides - 4) right angles.
The formula for the sum of the interior angles for a polygon having n sides = 2n - 4 right angles. 3240 ÷ 90 = 36 right angles : When 2n - 4 = 36 then 2n = 36 + 4 = 40 : n = 20 The regular polygon has 20 sides.
The sum of the interior angles of a polygon is 2n - 4 right angles - where n is the number of sides. So, 1080° = 1080/90 = 12 right angles If 2n - 4 = 12 then 2n = 16 : n = 8 The number of sides is 8.
The sum of the interior angles of a polygon is 2n - 4 right angles, where n is the number of sides.(2 x 32) - 4 = 60 right angles = 60 x 90 = 5400° .
4: Think of a square, 4 angles each 90o
Sum of angles in a polygon is (n -2)180. Hexagon has six sides. So the sum of angles is (6- 2)180. (4)180 =720
The sum of the exterior angles of a polygon is 360 degrees. If it is a regular polygon, then it has 360/4 = 90 vertices and so 90 sides.
a polygon with 4 right angles and 4 sides of the same length
Sum of interior angles of a polygon = (2n - 4)right angles 1260 = (2n - 4) x 90 1260 = 180n - 360 900 = 180n n = 5, it is a pentagon