To find the sum of the arithmetic sequence from 3 to 90 that is divisible by 5, we first identify the terms: the first term is 5 and the last term is 90. The sequence of terms divisible by 5 is 5, 10, 15, ..., 90. This is an arithmetic sequence where the first term (a = 5), the last term (l = 90), and the common difference (d = 5). The number of terms (n) can be calculated as ((l - a)/d + 1 = (90 - 5)/5 + 1 = 18). The sum (S_n) of the sequence can be calculated using the formula (S_n = n/2 \times (a + l)), resulting in (S_{18} = 18/2 \times (5 + 90) = 9 \times 95 = 855). Thus, the sum is 855.
Ninety is divisible by 3 because the sum of its digits (9 + 0 = 9) is divisible by 3. Additionally, it is divisible by 9 since the same sum (9) is also divisible by 9. Therefore, 90 can be evenly divided by both 3 and 9 without any remainder.
it depends what kind of polygon but the sum of the angles will equal a # divisible by 90
To determine if the number 23,456,910 is divisible by 90, it must be divisible by both 9 and 10. A number is divisible by 10 if it ends in 0, which 23,456,910 does. To check for divisibility by 9, the sum of its digits (2 + 3 + 4 + 5 + 6 + 9 + 1 + 0 = 30) must be divisible by 9, which it is not. Therefore, 23,456,910 is not divisible by 90.
Multiples of 90, like 90, 180 and 270 are divisible by 90.
90 is divisible by 10 since 90/10 = 9. It should be obvious that 90 is not divisible by 234,569 which is much larger than 90.
Ninety is divisible by 3 because the sum of its digits (9 + 0 = 9) is divisible by 3. Additionally, it is divisible by 9 since the same sum (9) is also divisible by 9. Therefore, 90 can be evenly divided by both 3 and 9 without any remainder.
it depends what kind of polygon but the sum of the angles will equal a # divisible by 90
To determine if the number 23,456,910 is divisible by 90, it must be divisible by both 9 and 10. A number is divisible by 10 if it ends in 0, which 23,456,910 does. To check for divisibility by 9, the sum of its digits (2 + 3 + 4 + 5 + 6 + 9 + 1 + 0 = 30) must be divisible by 9, which it is not. Therefore, 23,456,910 is not divisible by 90.
Well, isn't that a happy little question? Let's take a closer look. If a number is divisible by 5, it must end in 0 or 5. And if a number is divisible by 9, the sum of its digits must also be divisible by 9. When we add the digits of 90 (which is 9 + 0 = 9), we see that it is divisible by 9 but not by 5.
45 plus 45 is equal to 90. This is because addition is a basic arithmetic operation where two numbers are combined to find their total sum. In this case, adding 45 and 45 together results in a sum of 90.
Multiples of 90, like 90, 180 and 270 are divisible by 90.
90 is divisible by 10 since 90/10 = 9. It should be obvious that 90 is not divisible by 234,569 which is much larger than 90.
6, 9, 12, 30, 60, 90, 360, 690, 930, or (162,591). Here's a secret: If the sum of a number's digits is divisible by 3, then the number is divisible by 3. That's how you can tell quickly that 162,591 is divisible by 3.
==yes. 90 is divisible by 3 and 9==
Yes. 90 divided by 2 equals 45.
numbers which are divisible by 90 are the multiples of 90: 90, 180, 270, 360, 450, 540, 630,...
The number 90 is divisible by both 2 and 3.