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2304

Sum of an arithmetic progression = n/2 (2a + (n-1)d) where n is the number of items, a is the first item and d is the difference between them:

For the first 48 odd numbers:

  • n = 48
  • a = 1
  • d = 2

→ sum = 48/2 (2 x 1 + (48 - 1) x 2)

= 482

= 2304

The sum of the first n odd numbers is always n2

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Q: What is the sum of the first 48 odd numbers?
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