2304
Sum of an arithmetic progression = n/2 (2a + (n-1)d) where n is the number of items, a is the first item and d is the difference between them:
For the first 48 odd numbers:
→ sum = 48/2 (2 x 1 + (48 - 1) x 2)
= 482
= 2304
The sum of the first n odd numbers is always n2
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To find the sum of all odd numbers between 9 and 15, we first identify the odd numbers between these two values, which are 9, 11, 13, and 15. Next, we add these numbers together: 9 + 11 + 13 + 15 = 48. Therefore, the sum of all odd numbers between 9 and 15 is 48.
48 484 848
48
The odd numbers between these values are 49, 51, 53, 55, 57 and 59.
43,45,47,49,51,53,55,57,59,61,63