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Q: What are the three even integers whose sum is -138?

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Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138

33, 34, 35, 36

gcf of 138 and 207 is 69.

69 + 69 = 138.

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The integers are 44, 46 and 48.

136 + 138+ 140

Do-it-in-your-head method: The middle number MUST be a third of the total so 138 divided by 3 is 46, making your three numbers 44, 46 and 48. Shazam!

Divide the sum of the three consecutive integers by 3: 138/3 = 46. The smallest of these integers will be one less than 46 and the largest will be one more than 46, so the three consecutive integers will be 45, 46, and 47.

The three consecutive even numbers with a sum of 138 are 44, 46 and 48.

Let the first lowest number be x, then x + x + 1 + x + 2 + x + 3 = 138 4x + 6 = 138 4x = 138 - 6 4x = 132 x = 33 and the number are 33, 34, 35, and 36, add them and you will get 138

45, 46 and 47.

138 is, itself, an integer. It is impossible for any integer to lie between two consecutive integers.

The simplest way is to solve 4n + 6 = 138 for the smallest of them.

138/2 - 44 = 25 138/2 + 44 = 113 113 + 25 = 138 The two numbers are therefore 113 and 25.

The equation to solve this is... x + (x + 2) + (x + 4) = 138 x + x + x + 2 + 4 = 138 3x + 6 = 138 3x = 132 x = 44 x = 44 x + 2 = 46 x + 4 = 48 So, the three consecutive even numbers that add up to 138 are... 44, 46, & 48

33, 34, 35, 36

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