88
There are infinitely many, just like in base 10. In any base system, the number of perfect squares is the same. Take the natural (counting) numbers 1, 2, 3, .... Squaring each of these produces the perfect squares. As there are an infinite number of natural numbers, there are an infinite number of perfect squares. The first 10 perfect squares in base 5 are: 15, 45, 145, 315, 1005, 1215, 1445, 2245, 3115, 4005, ...
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
There is no single number here. The two seed numbers are 5 and 6; their squares sum to 61.
1, 4, 9, 16 UPDATE You missed one, you only wrote down 4, the first 5 are 1, 4, 9, 12, and 25.
5
9+16+25= 50
88
Here is a procedure that would do the job nicely: -- Make a list of all the perfect squares between 5 and 30. (Hint: They are 9, 16, 25, 36, and 49.) -- Find the sum by writing the numbers in a column and adding up the column.
81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.81. They are the perfect squares of numbers starting from 5.
It is: 4+9+25+49+121 = 208
sum of squares: 32 + 52 = 9 + 25 = 34 square of sum (3 + 5)2 = 82 = 64 This is a version of the Cauchy-Schwarz inequality.
There are infinitely many, just like in base 10. In any base system, the number of perfect squares is the same. Take the natural (counting) numbers 1, 2, 3, .... Squaring each of these produces the perfect squares. As there are an infinite number of natural numbers, there are an infinite number of perfect squares. The first 10 perfect squares in base 5 are: 15, 45, 145, 315, 1005, 1215, 1445, 2245, 3115, 4005, ...
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.
5
It squares numbers and add the totals together. The square of 2 is 4, the square of 5 is 25. The sum of squares of 2 and 5 is therefore 29. That would done in the SUMSQ function like this: =SUMSQ(2,5)