The sum of the interior angles of a polygon can be found using the formula:
(n-2) × 180°
Therefore, the interior angles of a pentacontagon; a fifty-sided polygon, will add up to:
(50-2) × 180°
(48) × 180°
8640°
50 internal angles though it will take some time to work out what they are.
The sum of the interior angles is 360.
The sum of the four interior angles of a trapezoid is 360 degrees.
(number of sides-2)*180 = sum of the interior angles
The sum of the 4 interior angles of a trapezoid add up to 360 degrees.
the answer is 8,640 the total interior angles of pentacontagon.
50 internal angles though it will take some time to work out what they are.
The sum of the interior angles is 360.
No, the interior angles of a triangle sum to 180o The interior angles of a quadrilateral sum to 360o.
The sum of the interior angles of a parallelogram is 360 degrees.
Interior angles of a triangle have a sum of 180 degrees.
A square always has a sum of 360 degrees for the interior angles.
A rhombus is a quadrilateral, so the sum of its interior angles is 360o.
The sum of the four interior angles of a trapezoid is 360 degrees.
(number of sides-2)*180 = sum of the interior angles
The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.The sum of the interior angles is (102-2)*180 = 18,000 degrees.
Do you mean the sum of interior angles? If so then it's: (number of sides -2)*180 = sum of interior angles