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The sum of the interior angles is (102-2)*180 = 18,000 degrees.

The sum of the interior angles is (102-2)*180 = 18,000 degrees.

The sum of the interior angles is (102-2)*180 = 18,000 degrees.

The sum of the interior angles is (102-2)*180 = 18,000 degrees.

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11y ago

The sum of the interior angles is (102-2)*180 = 18,000 degrees.

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Q: What is the sum of the angles of a polygon with 102 sides?
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What is the sum of the interior angles of a polygon with 25 sides?

The formula for the sum of the interior angles of a polygon is: 180 * (n - 2) where n is the number of sides of the polygon. So the sum of the angles of a polygon with 25 sides is 180 * 23 = 4,140.


What is the sum of the angle of a polygon with 102 sides?

Exterior angles add up to 360 degrees Interior angles add up 18000 degrees


What is the sum of the interior angles of a 102 sided-polygon?

Remember the two equations. Exterior angle = 360 / no. of sides. Interior angle = 180 - exterior angle. So for 102 sided polygon. exterior angle = 360/102 = 3.5294... Interior angle = 180 - 3.5294... = 176.4706.... Hence sum of the 102 sided polygon's angles is 102 X 176.4706 = 18,000 degrees. ( to nearest degree).


A convex polygon has 6 sides what is the sum of the measure of its interior angles?

a convex polygon has 6 sides . What is the sum of the measure of its interior angles?


What is the sum of the measures of the exterior angles of a regular polygon with ten sides?

What is the sum of the measures of the exterior angles of a regular polygon with ten sides


How many sides does a polygon have when the sum of its interior angles is equal to the sum of its exterior angles?

Four sides


The sum s of the measures of angles in a polygon of n sides?

The sum of the internal angles of a polygon of n sides is (n-2)*180 degrees.


How is the number of sides related to the sum of the angles in a polygon?

The sum of all the interior angles of a polygon with n sides is (n-2)*180 degrees.


What is a 102 sided polygon?

A 102-sided polygon is called a hectaicosagon. It is a polygon with 102 sides and 102 angles. The sum of the interior angles of a hectaicosagon can be calculated using the formula (n-2) x 180 degrees, where n is the number of sides. In this case, the sum of the interior angles of a hectaicosagon would be (102-2) x 180 = 18000 degrees.


What is the formula for finding the sum of the interior angles of a polygon?

(number of sides-2)*180 = sum of interior angles of a polygon


What is the sum of a 92 sided polygon?

The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?


What equals the sum of the angles in the polygon?

If the polygon has n sides, the sum of its interior angles is 180*(n-2) degrees.