Remember the two equations. Exterior angle = 360 / no. of sides. Interior angle = 180 - exterior angle. So for 102 sided polygon. exterior angle = 360/102 = 3.5294... Interior angle = 180 - 3.5294... = 176.4706.... Hence sum of the 102 sided polygon's angles is 102 X 176.4706 = 18,000 degrees. ( to nearest degree).
Four sides
The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?
35 sides
15 sides
The formula for the sum of the interior angles of a polygon is: 180 * (n - 2) where n is the number of sides of the polygon. So the sum of the angles of a polygon with 25 sides is 180 * 23 = 4,140.
Exterior angles add up to 360 degrees Interior angles add up 18000 degrees
Remember the two equations. Exterior angle = 360 / no. of sides. Interior angle = 180 - exterior angle. So for 102 sided polygon. exterior angle = 360/102 = 3.5294... Interior angle = 180 - 3.5294... = 176.4706.... Hence sum of the 102 sided polygon's angles is 102 X 176.4706 = 18,000 degrees. ( to nearest degree).
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
Four sides
The sum of the internal angles of a polygon of n sides is (n-2)*180 degrees.
The sum of all the interior angles of a polygon with n sides is (n-2)*180 degrees.
A 102-sided polygon is called a hectaicosagon. It is a polygon with 102 sides and 102 angles. The sum of the interior angles of a hectaicosagon can be calculated using the formula (n-2) x 180 degrees, where n is the number of sides. In this case, the sum of the interior angles of a hectaicosagon would be (102-2) x 180 = 18000 degrees.
(number of sides-2)*180 = sum of interior angles of a polygon
The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?
If the polygon has n sides, the sum of its interior angles is 180*(n-2) degrees.